Physics
chloethorpe13
2016-04-09 18:26:27
After an average acceleration of 3.95 m/s2 during 2.25 s, a car reaches a velocity of 15.3 m/s. find the car's initial velocity.
ANSWERS
msjohnson1094
2016-04-09 20:18:26

Since, We have avg. acceleration it can be put in place of accelaration in the given time period. v=15.3m/s a= 3.95m/s t= 2.25 s by using, a=(v-u)/t 3.95=(15.3-u)/2.25 (3.95*2.25)-15.3= -u 8.8875-15.3= -u  -6.4125= -u ⇒ u= 6.4125 m/s

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