Answer: increases. You can infere that from the fact that the pressure is proportional the the concentration, which in turn you can deduce from the ideal gas law: pV = nRT => p = nRT / V = (n/V) RT Where n/V is the concentration. So, you got that at constant T, p is proportional to the number concentration, which leads you to the conclusion that if the pressure exerted on a gas increases, the reaction rate increases.
The reaction rate refers to the change in concentration of a reactant or product per unit of time. if the pressure exerted on a gas increases, the reaction rate ____.