Mathematics
kunihiro56
2016-04-11 19:59:12
figure out 4x^2y^0/2y^-1
ANSWERS
Pensick294
2016-04-11 21:47:34

[latex] cfrac{4x^2y^0}{2y^{-1}} = cfrac{2x^2*1}{y^{-1}} =2x^2*y^1=2x^2y[/latex]

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