Mathematics
mzbrown11
2016-04-11 20:22:42
a total number of 6 family members will participate in a portrait. If 2 of the family members may sit in the front row how many combinations of family members may sit in the front trow
ANSWERS
Thefatpolak
2016-04-12 00:35:06

Since order is not important, you must use the "n choose k" formula for unique combinations... n!/(k!(n-k)!), n=total possible choices, k=number of choices made 6!/(2!(6-2)!) 6!/(2!4!) 15

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