We have two points, (3,0) and (0,-3). So we can find the slope of the line: m=(y2-y1)/(x2-x1) m=(-3-0)/(0-3) m=-3/-3 m=1 so far for the line y=mx+b we have: y=x+b, b is the y intercept which we were told is -3 so y=x-3 The above is called the slope-intercept form of a line, y=mx+b, the standard form of a line is ax+by=c, so we need to get both variables on one side of the equation.. y=x-3 subtract x from both sides -x+y=-3 While the above may be acceptable to some, technically the coefficient of x should be expressed as a positive value, so we should divide the above "solution" by -1 to get: x-y=3
Write the standard form of the line that contains a y-intercept of -3 and passes through the point (3, 0). Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.