John flies from Atlanta, Georgia to San Francisco, California. It takes 5.6 hours to travel 2100 miles against the head wind. At the same time, Debby flies from San Francisco to Atlanta. Her plane travels with the same average airspeed, but with a tail wind, and her flight takes only 4.8 hours. Write a system of equations that relates time, airspeed, and wind speed to distance for each traveler. Solve the system to find the airspeed. a. 406.25 mi/h c. 519 mi/h b. 408.45 mi/h d. 480 mi/h

ANSWERS

2016-04-12 18:33:15

John : distance = 2100 mi ; time = 5.6 hrs ; rate = d/t = 2100/5.6 = 375 mph Debby: distance = 2100 mi ; time = 4.8 hrs ; rate = d/t = 2100/4.8 = 437.5 mph Let air speed be a and wind speed be w; then: a+w=437.5 mph a-w=375 mph Solve the system to find the air speed. Add the two equations: a+w=437.5 a-w=375 becomes 2a = 812.5 a=812.5/2 air speed = 406.25 mph

2016-04-12 18:34:30

The answer is a. 406.25MPH

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