32.7 grams of water vapor takes up how many liters at standard temp and pressure (273 K and 100 kPa)

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2016-04-14 03:45:26

You just need to convert the mass in grams to number of moles and use the ideal gas equation, pV = n RT where p = 100 kPa, T = 273 K, V is the volume searched, n is the number of moles and R is the unviersal constant of gases = 8.314 J / K * mol 1) Number of moles = mass in grams / molar mass => n = 32.7 g / 18.0 g/mol = 1.81667 moles 2) pV = nRT => V = nRT / p V = 1.81667 moles * 8.314 (liter*KPa /k*mol) * 273K / (100 KPa) = 41.2 liter Answer: 41.2 liters

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