If 1.20 moles of an ideal gas occupy a volume of 18.2 l at a pressure of 1.80 atm, what is the temperature of the gas, in degrees celsius?

ANSWERS

2016-04-14 17:00:54

We can calculate for temperature by assuming the equation for ideal gas law: P V = n R T Where, P = pressure = 1.80 atm V = volume = 18.2 L n = number of moles = 1.20 moles R = gas constant = 0.08205746 L atm / mol K Substituting to the given equation: T = P V / n R T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K) T = 332.70 K We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore T = 59.55 ˚C

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