Mathematics
tatumw98
2016-04-17 18:44:57
what is the sixth term of a geometric sequence where a1 equals 1024 and a4 equals -16
ANSWERS
lizy25
2016-04-17 19:12:37

-16/1024=(ar^4)/(ar) -1/64=r^3 (-1/64)^(1/3)=r -1/4=r -0.25=r 1024=a(-0.25^1) -4096=a a(n)=-4096(-0.25^n) a(6)=-4096(-0.25^6) a(6)=-1

ADD ANSWER