Mathematics
JacobDecillis
2016-04-21 11:39:27
Find the half-life of an element which decays by 3.411% each day. Hint: use y = ab^t.
ANSWERS
Anika01
2016-04-21 18:34:05

a/2=a((100-3.411)/100)^t a/2=a(0.96589)^t 0.5=0.96589^t  ln(0.5)=t(ln(0.96589)) t=ln(0.5)/ln(0.96589) t≈19.97 days (to nearest hundredth of a day)

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