The parabola has a vertex of (1,-16) and y intercept of (0,-15) that crosses the x axis in two places. one x intercept is (5,0) what is the other x intercept

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2016-04-23 12:40:28

vertex form is: y = a(x - 1)^2 - 16 where a is a cosntant at y intercept we have -15 = a^2 - 16 a^2 = 1 so equation of the parabola is y = (x-1)^2 - 16 the equation of symmetry is x = 1 and both roots are same distance either side of the point (1,0) so the other x-intercept is 1 - 4 = (-3,0)

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