Mathematics
Micheal888
2016-04-25 08:05:27
What is the perimeter of the isosceles trapezoid that has vertices of A(-3,5) B(3,5) C(5,-3) and D(-5,-3)?
ANSWERS
ForrestStroman
2016-04-25 12:21:20

Given the order of the vertices of the trapezoid (ABCD) and the coordinates, we can calculate the length of each side and add them up to get the perimeter. We know A(-3,5) B(3,5) C(5,-3) and D(-5,-3), then mAB=(3-(-3))=6 (since the other coordinate= 5 is the same for A & B. mBC=sqrt((5-3)^2+(-3-5)^2)=sqrt(4+64)=sqrt(68) mCD=(5-(-5))=10  (since the other coordinate=-3 is the same for C & D. m(DA)=sqrt((-5-(-3))^2+(-3-(-5))^2)=sqrt(68) Therefore perimeter =6+sqrt(68)+10+sqrt(68) =16+2sqrt(2^2 * 17) =16+4sqrt(17)   [exact] =32.5 [approx.]

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