Why is the answer (A)?
ANSWERS
2016-04-25 18:06:06
[latex] frac{1}{2}x^2+mx-5=0 \ \ x= frac{-mб sqrt{m^2-4* frac{1}{2}*(-5) } }{2* frac{1}{2} }= frac{-mб sqrt{m^2+10} }{1}=-mб sqrt{m^2+10} [/latex]
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[latex] frac{1}{2}x^2+mx-5=0 \ \ x= frac{-mб sqrt{m^2-4* frac{1}{2}*(-5) } }{2* frac{1}{2} }= frac{-mб sqrt{m^2+10} }{1}=-mб sqrt{m^2+10} [/latex]