Mathematics
alyssataylor
2016-04-25 15:08:27
Why is the answer (A)?
ANSWERS
graceadele4
2016-04-25 18:06:06

[latex] frac{1}{2}x^2+mx-5=0 \ \ x= frac{-mб sqrt{m^2-4* frac{1}{2}*(-5) } }{2* frac{1}{2} }= frac{-mб sqrt{m^2+10} }{1}=-mб sqrt{m^2+10} [/latex]

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