Mathematics
rylieschilling
2016-04-26 11:06:57
Solve log2(6-2x)-log2x=3
ANSWERS
ModestoStofflet
2016-04-26 12:44:44

Assuming you have log in base 2. Join logarithms (always): log2(6-2x)-log2(x) = log2( (6-2x/x) ) Then get rid of it! :) (6-2x)/x = 2^3=8, Solve the equation: 6-2x=8x ---> 10x=6 ---> x = 3/5.

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