Help me find solutions to this equation and write the answers in radians in terms of pi . Thanks!

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2016-04-29 12:51:05

okay so just use it as an equation. if 2sin0 + 3^(1/2) = 0 2 sin0 = - 3^(1/2) then sin0 = (-3^ (1/2))/2 do sin^-1(-[latex] frac{-sqrt{3}}{2} [/latex]) = -1/3pi we want it between 0 < x < 2pi so add 2pi (equivalent to 360degrees) = 5/3pi and to find the second value, (2pi - 5/3pi) + pi = 4/3pi answers are 5/3pi and 4/3pi

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