Mathematics
Uptegrove212
2016-04-30 04:13:12
What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x + 10 and passes through the point (15, –5)? The equation of the line in slope-intercept form is y =-5/3 x + ____
ANSWERS
ananaple64
2016-04-30 10:50:43

y = 3/5x + 10...slope here is 3/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So we need a slope of -5/3 y = mx + b slope(m) = -5/3 (15,-5)...x = 15 and y = -5 now we sub for b, the y int -5 = -5/3(15) + b -5 = -25 + b -5 + 25 = b 20 = b so ur perpendicular equation is : y = -5/3x + 20

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