Write an equation of a line that passes through the point (0,-15) and is parallel to 5x-4y=12

ANSWERS

2016-05-01 11:09:00

5x-4y=12 4y = 5x - 12 y = 5/4x - 3 slope = 5/4 b = -15 so equation y = 5/4x - 15

2016-05-01 11:10:15

write given equation in slope intercept form 4y = 5x - 12 y = (5/4)x - 3 so the slope of the line is 5/4. so the equation we want has also slope 5/4 because it is parallel to given line. y - y1 = (5/4)(x - x1) y1 = -15 and x1 = 0 :- y + 15 = (5/4) x y = (5/4)x - 15 is the required equATION changing to standard form we get 4y = 5x - 60 5x - 4y = 60

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