Physics
kking
2021-03-18 21:57:12
A 0.0600-kilogram ball traveling at 60.0 meters per second hits a concrete wall. What speed must a 0.0100-kilogram bullet have in order to hit the wall with the same magnitude of momentum as the ball? (1) 3.60 m/s (3) 360. m/s (2) 6.00 m/s (4) 600. m/s
ANSWERS
EttieProbst
2021-03-19 03:59:22

     The momentum of ball is given by: [latex]Delta Q=mv \ Delta Q=6*10^{-2}*60 \ Delta Q=3.6kg*m/s[/latex]         Since both have the same momentum, we have: [latex]Delta Q=MV \ 3.6=10^{-2}V \ oxed {V=360m/s}[/latex] Number 3 If you notice any mistake in my english, please let me know, because i am not native.    

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