Physics
ACEJOHNNY24
2021-03-19 05:11:57
The Hubble telescope’s orbit is 5.6 × 10^5 meters above Earth’s surface. The telescope has a mass of 1.1 × 10^4 kilograms. Earth exerts a gravitational force of 9.1 × 10^4 newtons on the telescope. The magnitude of Earth’s gravitational field strength at this location is (1) 1.5 × 10^−20 N/kg (3) 8.3 N/kg (2) 0.12 N/kg (4) 9.8 N/kg
ANSWERS
orangeladybug282
2021-03-19 07:11:08

(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg

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