The Hubble telescope’s orbit is 5.6 × 10^5 meters
above Earth’s surface. The telescope has a mass
of 1.1 × 10^4 kilograms. Earth exerts a gravitational
force of 9.1 × 10^4 newtons on the telescope. The
magnitude of Earth’s gravitational field strength
at this location is
(1) 1.5 × 10^−20 N/kg (3) 8.3 N/kg
(2) 0.12 N/kg (4) 9.8 N/kg

ANSWERS

2021-03-19 07:11:08

(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg

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