A horizontal 20.-newton force is applied to a 5.0-kilogram box to push it across a rough,
horizontal floor at a constant velocity of 3.0 meters per second to the right.
Calculate the coefficient of kinetic friction between the box and the floor. [Show all work, including
the equation and substitution with units]

ANSWERS

2021-03-20 13:36:16

The formula to work out the coefficient of dynamic (kinetic) friction is F=uR where F is the force applied, u is the coefficient of dynamic friction, and R is the reaction force. This is based on the principle the object is moving at a constant velocity which is the case in this question. Rearranging this we get u=F/R Substituting in the values we get u=20/50=2/5=0.4 Therefore the coefficient of kinetic friction between the box and the floor is 0.4

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