Physics
ZofiaHursey611
2021-03-21 06:44:42
When a spring is compressed 2.50 × 10^–2 meter from its equilibrium position, the total potential energy stored in the spring is 1.25 × 10^–2 joule. Calculate the spring constant of the spring. [Show all work, including the equation and substitution with units.]
ANSWERS
JenineWeenum
2021-03-21 13:15:10

     The working of a spring is given by: [latex]T_{el}= frac{kDelta x^2}{2} [/latex]        Entering the unknowns, we have: [latex]T_{el}=frac{kDelta x^2}{2} \ 1.25*10^{-2}*2*J=k(2.5*10^{-2}m)^2 \ k= frac{2.5*10^{-2}*J}{(2.5*10^{-2}m)^2} \ k=40* frac{J}{m^2} \ k=40 frac{N*m}{m^2} \ oxed {k=40* frac{N}{m} }[/latex]   If you notice any mistake in my english, please let me know, because i am not native.

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