Physics
Scotty383
2021-03-21 16:20:27
A 0.50-kilogram cart is rolling at a speed of 0.40 meter per second. If the speed of the cart is doubled, the inertia of the cart is (1) halved (3) quadrupled (2) doubled (4) unchanged
ANSWERS
Angelnichole
2021-03-21 19:44:04

     The inertia of moving body is calculated from the amount of moviment equation, given by: [latex]Q=mv[/latex]        Let us consider the index 1 to the initial situation, and the index 2 to the final situation. Doing this, we get:  [latex] left { {{Q_{1}=mv_{1}- extgreater Q_{1}=0.5*0.4- extgreater Q_{1}=0.2 frac{kg*m}{s} } atop {Q_{2}=mv_{2}- extgreater Q_{2}=0.5*2*0.4- extgreater Q_{1}=0.4 frac{kg*m}{s}}} ight. [/latex]         Comparing the results: [latex]k= frac{Q_{2}}{Q_{1}} \ k= frac{0.4}{0.2} \ oxed {k=2}[/latex]        Therefore, the inertia is doubled. Number 2 If you notice any mistake in my english, please let me know, because i am not native.

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