A clerk moves a box of cans down an aisle by pulling on a strap attached to the box. The clerk pulls with a force of 185.0 N at an angle of 25.0 degrees with the horizontal. The box has a mass of 35.0 kg, and the coefficient of kinetic friction between the box and the floor is 0.450. Find the acceleration of the box.

ANSWERS

2021-04-11 00:42:57

horizontal force exerted on the box = 185 cos(25) = 167.7 N coefficient of friction k = 0.450 friction force = kmg = 0.450 x 35 x 9.8 = 154.3 N total horizontal force on the box = 167.7 - 154.3 = 13.4 N acceleration = F/m = 13.4 / 35 = 0.383 m/s^2

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