If 8.00 mol of NH3 reacted with O2, how many moles of H2O will be produced?
4NH3(g) + 7O2 (g) -> 4NO2 + 6H2 O(g)
ANSWERS
2015-11-17 19:33:37
4 mol .................................................... 6 mol 4NH3(g) + 7O2(g) ----> 4NO2(g) + 6H2O(g) 8 mol ........................................................ X X = (6×8)/4 X = 48/4 = 12 moles H₂O :•)
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