Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1.

ANSWERS

2021-05-03 15:28:23

Vertex: (-5, 2) Standard form of a vertical parabola (x - h)^2 = 4p (y-k) (x - (5))^2 = 4p (y -2) (x + 5)^2 = 4p (y-2) p is the distance between the vertex and either the focus or the directrix: p = 3 Final equation: (x +5)^2 = 4*3 (y-2) (x + 5)^2 = 12 (y-2)

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