Vertical asymptotes are the x-values for which a particular function is undefined; With linear reciprocal functions like the one given, it will be when the denominator equates to 0 as it is impossible to divide any number by 0; So we just have to equate the denominator to 0 and rearrange to give x: x - 1 = 0 x = 1 The line x = 1 is the vertical asymptote for this function. Horizontal asymptotes are the y-values for which a particular function is undefined; Finding the horizontal asymptote for linear reciprocal functions is quite simple; For this kind of function, where there is no x term in the numerator, the horizontal asymptote is just equivalent to the constant added to the fraction (note: having no added constant is the same as having an added 0); So: F(x) = 1/(x - 1) = (1/(x - 1)) + 0 The horizontal asymptote is y = 0 for this function. If it was F(x) = (1/(x - 1)) + 1, the horizontal asymptote would be y = 1.
At what value of x does the graph of the following function F(x) have a vertical asymptote? F(x)=1/x-1