alrigty in form [latex]y=a(x-h)^2+k[/latex] the vertex is (h,k) the constant, a, deterimines the size and direction if a>0, then the parabola opens up and the vertex is the minimum if a<0 then the parabola opens down and the vertex is the maximum so we are given [latex]y=1(x-(-2))^2+4[/latex] 1>0 so it opens up vertex is (-2,4) the vertex is a minimum the vertex is (-2,4) and the graph has a minimum
Select the statements that are true for the graph of y=(x+2)^2+4 The vertex is (2, 4) . The graph has a minimum. The vertex is (−2, 4) . The graph has a maximum.