Mathematics
Taylormarie1018
2015-11-07 06:18:57
Complete the square for the following quadratic function: y = -6x2 + 36x - 12 Then, graph the function. Point out the line of symmetry and state the maximum or minimum value.
ANSWERS
Alejandrina452
2015-11-07 08:36:30

y = -6x^2 + 36x - 12 y = -6(x^2 - 6x) - 12 y =  -6[ (x - 3)^2 - 9] - 12 y =  -6(x - 3)^2 + 54 - 12 y = -6(x - 3)^2 + 42 the vertex is at x = 3  so line of symmetry is x = 3 it will have a maximum value of 42  (as the vertex is at (3,42)

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