Mathematics
jozim
2015-11-10 14:24:42
How many solutions does the following equation have? ln(x2 + 4x − 5) = 0
ANSWERS
malikamirclay
2015-11-10 20:12:03

alrighty remember [latex]log_a(b)=c[/latex] means [latex]a^c=b[/latex] and [latex]ln(x)=log_e(x)[/latex] and [latex]x^0=1[/latex] for all real values of x so [latex]ln(x^2+4x-5)=0[/latex] means [latex]log_e(x^2+4x-5)=0[/latex] means [latex]e^0=x^2+4x-5[/latex] which simplifies to 1=x²+4x-5 minus 1 both sides 0=x²+4x-6 use quadratic formula or complete the square [latex]x=-2+sqrt{10}[/latex] and [latex]x=-2-sqrt{10}[/latex] 2 solutions

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